Heat required to convert one gram of ice at 0∘C into steam at 100∘C is (given Lstream = 536 cal/gm)
716 calorie
Conversion of ice ( 0∘C ) into steam ( 100∘C ) is as follows
Heat required in the given process = Q1+Q2+Q3
= 1×80+1×1×(100−0)+1×536=716cal