Heating of ammonium dichromate produces all these compounds except:

_{3}

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_{2}

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_{2}

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_{2}

_{3}

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Solution

The correct option is A NH $_{3}$
Solid ammonium carbonate decomposes as it is heated.
Balanced equation:
$(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + N_{2} + H_{2} O$
Thus, ammonia $(N H_{3})$ is not obtained as a product int the given reaction.

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Similar questions

(NH₄)₂Cr₂O₇ $\overset{}{\to}$ N₂ + Cr₂O₃ + 4H₂O. What volume of nitrogen at STP, will be evolved when 63 g of ammonium dichromate is decomposed? (H = 1, N = 14, O = 16, Cr = 52)

Q. How many of the following compounds liberate

N H_{3}

on heating?

(N H_{4})_{2} S O_{4}, (N H_{4})_{2} C O_{3}, N H_{4} C l, N H_{4} N O_{3}, (N H_{4})_{2} C r_{2} O_{7}, (N H_{4})_{2} C_{2} O_{4}

Solid ammonium dichromate decomposes as the equationr:

$(N H_{4} 4)_{2} C r_{2} O_{7} \to N_{2} + C r_{2} O_{3} + 4 H_{2} O$
If 63 g of sammonium dichromate decomposes, calculate:
(a) the quantity in moles of $(N H_{4})_{2} C r_{2} O_{7}$
(b) the qunatity in moles of nitrogen formed
(c) the volume of $N_{2}$ evolved at STP

(d) the loss of mass
(e) the mass of chromium (iii) oxide formed at the same time.

(N H_{4})_{2} C r_{2} O_{7},

on heating liberates a gas. The same gas will be obtained by:

Q. The correct order of magnitude of bond angles among the compounds

C H_{4}, N H_{3} a n d H_{2} O

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Heating of ammonium dichromate produces all these compounds except:

The correct option is A NH3Solid ammonium carbonate decomposes as it is heated. Balanced equation: (NH4)2Cr2O7→Cr2O3+N2+H2OThus, ammonia (NH3) is not obtained as a product int the given reaction.

The correct option is A NH $_{3}$
Solid ammonium carbonate decomposes as it is heated.
Balanced equation:
$(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + N_{2} + H_{2} O$
Thus, ammonia $(N H_{3})$ is not obtained as a product int the given reaction.