Question

Helium gas at 1 atm and $S{O}_2$ at 2 atm pressure, temperature being the same, are released seprately at the same moment into 1m long evacuated tubes of equal diameters. If helium reaches the other end of the tube in ts, what distance $S{O}_2$ would traverse in the same time interval in the other tube ?

• A. 25 cm
• B. 50 cm
• C. 60 cm
• D. 75 cm

Answer 1

The correct option is B

50 cm

$\frac{r_{He}}{r_{S{O}_2}}=\frac{\frac{100}{t}}{\frac{x}{t}}=\frac{P_{He}}{P_{S{O}_2}}\sqrt{\frac{M_{S{O}_2}}{M_{He}}}=\frac{1}{2}\times \sqrt{\frac{64}{4}}=2$
or $x=50cm$