CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Ideal Gas Equation

Helium gas at...

Question

Helium gas at $27^{o} C$ is subjected to a pressure change from 5 atm to 2 atm at constant temperature. The initial volume of the gas was $10 d m^{3}$ . Calculate the change in volume of gas in $d m^{3}$ .

Open in App

Solution

$P V = n R T \Rightarrow P V = c o n s t a n t =$

$∴ P_{1} V_{1} = P_{2} V_{2}$

$\Rightarrow 5 \times 10 = 2 \times V_{2} \Rightarrow V_{2} = 25$

$∴$ change in volume = $15 d m^{3}$

Suggest Corrections

thumbs-up

0

Similar questions

At constant pressure, a sample of helium gas has a volume of

800 m l

27^{o} C

. Calculate the temperature at which the volume will become

20

% of its initial volume.

Q. At constant pressure, a sample of helium gas has a volume of

800 m l

27^{o} C

. Calculate the percentage increase in volume, if temperature is

90^{0} C

.

Q. A gas expands isothermally against constant external pressure of 1 atm from a volume of 10 dm³ to a volume of 20 dm³. In the process, it absorbs 800J of thermal energy from surroundings. Calculate the value of internal energy change.

Q. Two moles of helium gas (

γ = 5 / 3

) are initially at a temperature of

27^{o} C

and occupy a volume of

20 l i t r e

. The gas is first expanded at constant pressure until the volume is doubled. It then undergoes adiabatic change until the temperature returns to its initial value. If total work done by the gas is

- x k c a l

x

Q. A gas expands isothermally against a constant external pressures of 1 atm from a volume of

10 d m^{3}

20 d m^{3}

. It absorbs 800 J of thermal energy from its surroundings. Calculate the change in internal energy

(Δ E)

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

The Ideal Gas Equation

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Ideal Gas Equation

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon