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Please help me with the following

The sides of a triangle touch a circle. Sides AB, BC, CA touch the circle at points P, Q, R respectively. Prove that:

1. AP+BQ+CR=BP+CQ+AR

2.AP +BQ+CR=1/2 *perimeter of 🔺 ABC

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In the given figure, the incircle of $△ A B C$ touches the sides AB, BC and CA at the points P, Q, R respectively. Show that
$A P + B Q + C R = B P + C Q + A R$
$= \frac{1}{2} (P e r i m e t e r o f △ A B C)$
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The incircle of triangle ABC touches sides AB, BC and CA at P, Q and R respectively. If AP = BQ = CR = 2 cm, then which of the following statements are true?

In the figure below, the lines AB, BC, CA touch the circle at P, Q, R.

Prove that the perimeter of the triangle is 2(AP + BQ + CR)

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△ A B C

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Hello Please help me with the following The sides of a triangle touch a circle. Sides AB, BC, CA touch the circle at points P, Q, R respectively. Prove that: 1. AP+BQ+CR=BP+CQ+AR 2.AP +BQ+CR=1/2 *perimeter of 🔺 ABC

Dear student, We found a similar question to the one that you posted. Please check it out here. Regards

Hello

Please help me with the following

The sides of a triangle touch a circle. Sides AB, BC, CA touch the circle at points P, Q, R respectively. Prove that:

1. AP+BQ+CR=BP+CQ+AR

2.AP +BQ+CR=1/2 *perimeter of 🔺 ABC

Dear student,

We found a similar question to the one that you posted. Please check it out here.

Regards