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Question

Hemispherical bowl is made of steel 0.25 cm thick. Inner radius of bowl is 5 cmfind outer CSA .

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Solution

Inner radius of hemispherical bowl = 5 cm

Thickness of the bowl = 0.25 cm

∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm

= 5.25 cm

Outer CSA of hemispherical bowl = 2r2

Therefore, the outer curved surface area of the bowl is 173.25 cm2.


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