Henry made a four-sided table with equal sides and all angles measuring 90°. Which of the following statements about the possible shape of the table is true?

Statement I: It $could be$ a parallelogram because all angles are 90° and all sides are equal.
Statement II: It $could be$ a rectangle or a trapezoid because all angles are 90° and all sides are equal.
Statement III: It $could be$ a square or a rhombus because all sides are equal and all angles are 90°.

Only statement III

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Statement I and statement III

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Statement III and statement IV

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Statement I and statement II

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Solution

The correct option is B Statement I and statement III
All sides of the table are equal and all its angles are 90°. Hence, we can conclude that the given figure is a square.

A square $can be$ a parallelogram. So, statement I is correct.
A square $cannot be$ a trapezoid. So, statement II is incorrect.
A square is a special type of rhombus. So, statement III is correct.

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A. A parallelogram, where diagonals are equal,all sides equal and all the angles are

90^{\circ}

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B. A parallelogram, where diagonals and opposite sides are equal, and all the angles are

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Match the following:
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Match the following:

$\begin{matrix} Quadrilateral & Properties 1. Trapezium & A) A parallelogram, where diagonals bisect at right angles, all sides are equal and none of the angles are equal to 90^{\circ} 2. Square & B) A quadrilateral, where only one pair of opposite sides is parallel and unequal 3. Rectangle & C) A parallelogram, where diagonals are equal, all sides equal and all the angles are 90^{\circ} 4. Rhombus & D) A parallelogram, where diagonals and opposite sides are equal, and all the angles are 90^{\circ} \end{matrix}$

Q. A quadrilateral whose all four sides are equal and all four angles are equal to 90° is called .

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