Henry's Law constant for $C O_{2}$ in water is $1.67 \times 10^{8}$ Pa at 298 K. Calculate the quantity in 1 L of soda water when packed under 2.5 atm pressure at 298 K.

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Solution

We know Henry's Law:
$P = K_{H} \times x$

$\Rightarrow x = \frac{2.5 \times 1.013 \times 10^{5}}{1.6 \times 10^{8}}$
$\Rightarrow \frac{n_{C O_{2}}}{1000 / 18} = \frac{2.5 \times 1.013}{1.6 \times 1000}$

$\Rightarrow n_{C O_{2}} = \frac{25}{16} \times \frac{1.013}{18}$
$\Rightarrow$ mass of $C O_{2}$ dissolved $= \frac{25}{16} \times \frac{44 \times 1.013}{18}$

$= 3.86 g r a m s .$

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