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Henry's Law

The quantity ...

Question

The quantity of ${C O}_{2}$ in 500ml of soda water when packed under 2.5 atm ${C O}_{2}$ pressure at 298K is ____ gm ( Henry's law constant $1.67 \times 10^{8}$ pa at 298K)

0.64

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1.86

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6.4

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18.6

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Solution

The correct option is A 1.86

According to Henry's law,

p_{C O_{2}} = K_{H} x

Here

x

is the mole fraction of carbon dioxide in the carbon dioxide water mixture.

p_{C O 2} = 2.5 a t m = 2.5 \times 1.01325 \times 10^{5} P a = 2.533125 \times 10^{5} P a

x = \frac{m o l e s o f C O_{2}}{m o l e s o f C O_{2} + m o l e s o f H_{2} O}

Hence,

According to Henry's law,

p_{C O_{2}} = K_{H} x

∴x=mole fraction=pCO2KH=2.533125×1051.67×108=1.51×10−3

Here moles of

C O_{2}

is negligible in the denominator as compared to moles of

H_{2} O

500 ml of water = 500g of water =

\frac{500}{18}

= 27.78 moles of water.

So, moles of

\frac{C O_{2}}{27.78} = 1.51 \times 10^{- 3}

or moles of

C O_{2} = 0.042 m o l e s .

Hence the amount of

C O_{2}

in 500 ml of soda water is

0.042 \times 44 = 1.86 g

Hence, the correct option is

B

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Similar questions

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the quantity of

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The quantity of CO2 in 500ml of soda water when packed under 2.5 atm CO2 pressure at 298K is ____ gm ( Henry's law constant 1.67×108 pa at 298K)

The quantity of ${C O}_{2}$ in 500ml of soda water when packed under 2.5 atm ${C O}_{2}$ pressure at 298K is ____ gm ( Henry's law constant $1.67 \times 10^{8}$ pa at 298K)