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Question

Henry's law constant for the solubility of N2 gas in water at 298K is 1.0×105 atm. The mole fraction of N2 in air is 0.6. The number of moles of N2 from air dissolved in 10 moles of water at 298K and 5 atm pressure is


A

3.0 × 10-4

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B

4.0 × 10-5

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C

5.0 × 10-4

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D

6.0 × 10-6

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Solution

The correct option is A

3.0 × 10-4


Partial pressure of N2 in air (PN2)=PTotal×XN2(in air)PN2(in air)=KH×XN2(in H2O)5×0.6=1×105×XN2(in H2O)

XN2 in 10 moles of water =5×0.61×105=3×105XN2=nN2nN2+nH2O3×105=nN2nN2+10nN2×3×105+3×105×10=n23×104=nN2(13×105)nN2=3×104


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