1.The Henry's law constant for the solubility of N2gas in water at 298k is 10^5 atm.The mole fraction of N2 is 0.8.Find the number of N2 from air dissolved in 10 moles of water at 298K and 5 atm pressure

2.How many moles in 1litre of water

Q. The Henry's law constant for the solubility of

N_{2}

gas in water at 298 K is

1.0 \times 10^{5} a t m

. The mole fraction of

N_{2}

in air is 0.8. The no. of moles of

N_{2}

in 10 moles of water of 298 K and 5 atm pressure is:

Q. The Henry's law constant for the solubility of

N_{2}

gas in water at

298 K

1.0 \times 10^{5} a t m

. The mole fraction of

N_{2}

in air is

0.8

. The number of moles of

N_{2}

from air dissolved in

10

moles of water at

298 K

and

5

atmospheric pressure is

x \times 10^{- y}

. Find the value of

\frac{x}{y}

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Henry's law constant for the solubility of N2 gas in water at 298K is 1.0×105 atm. The mole fraction of N2 in air is 0.6. The number of moles of N2 from air dissolved in 10 moles of water at 298K and 5 atm pressure is

Henry's law constant for the solubility of $N_{2}$ gas in water at 298K is $1.0 \times 10^{5}$ atm. The mole fraction of $N_{2}$ in air is 0.6. The number of moles of $N_{2}$ from air dissolved in 10 moles of water at 298K and 5 atm pressure is