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Question

Henry’s law constant for the solubility of nitrogen gas in water at 298 K is 1.0×105atm. The mole fraction of nitrogen in air is 0.8. The number of moles of nitrogen from air dissolved in 10 mol of water at 298 K and 5 atm pressure is
  1. 4.0×104atm
  2. 4.0×105atm
  3. 5.0×104atm
  4. 4.0×105atm


Solution

The correct option is A 4.0×104atm
PN2=5×0.8=4
Applying Henry’s law, we get
PN2=KH×XN2
or 4=105×XN2
XN2=4×105
nnitrogennnitrogen+nH2O=4×105
Or nnitrogennnitrogen+10=4×105
Or nnitrogen=4×104
 

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