Question

Henry’s law constant for CO₂ in water is 1.67 × 10⁸ Pa at 298 K. Calculate the quantity of CO₂ in 500 mL of soda water when packed under 2.5 atm CO₂ pressure at 298 K.

Answer 1

It is given that:

K_H = 1.67 × 10⁸ Pa

= 2.5 atm = 2.5 × 1.01325 × 10⁵ Pa

= 2.533125 × 10⁵ Pa

According to Henry’s law:

= 0.00152

We can write,

[Since, is negligible as compared to]

In 500 mL of soda water, the volume of water = 500 mL

[Neglecting the amount of soda present]

We can write:

500 mL of water = 500 g of water

= 27.78 mol of water

Now,

Hence, quantity of CO₂ in 500 mL of soda water = (0.042 × 44)g

= 1.848 g