Henrys law constant $[K_{H}]$ for four gases at 293 K are,
$H e [144.97 K b a r], H_{2} [69.16 K b a r], N_{2} [76.48 K b a r], O_{2} [34.86 K b a r]$ .
Which gas is more soluble in water at a given pressure.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $O_{2}$

Suggest Corrections

Similar questions

Q. The value of Henry's law constant for some gases at

293 K

is given below. Arrange the gases in the increasing order of their solubility.

H e = 144.97 k b a r

;

H_{2} = 69.16 k b a r

N_{2} = 76.48 k b a r

;

O_{2} = 34.86 k b a r

Gases posses charcteristic critical temperature which depends upo the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.

$\begin{matrix} G a s e s & H_{2} & H e & O_{2} & N_{2} C r i t i c a l t e m p e r a t u r e i n K e l v i n & 33.2 & 5.3 & 154.3 & 126 \end{matrix}$