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pH of Salts

Here A or B i...

Question

Here A or B is

CH=CH

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KOH

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CH₂ =CH₂

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KNO₃

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Solution

The correct options are
A
CH=CH

B
KOH

This is an example of kolbe's electrolysis method.

By Kolbe's Electrolysis Method:

Sodium or potassium salt of maleic or fumaric acid on electrolysis gives acetylene and $C O_{2}$ at anode whereas hydrogen at cathode.

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Similar questions

A g N O_{3}

C H_{2} = C H - C H = C H - + C H_{2}

C H_{2} = C H - + C H - C H = C H_{2}

C H_{2} = C H - + C H - - C H - + C H_{2}

+ C H_{2} - C H = C H - - C H - + C H_{2}

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

C H_{2} = C H - C H = C H - \oplus N H_{3}

\oplus C H_{2} - C H = C H - ⊖ C H - \oplus N H_{3}

\oplus C H_{2} - C H = C H - C H = N H_{3}

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

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