Here is a table which gives the information about the total rainfall for several months compared to the average monthly rains of a town. Write each decimal in the form of rational number $\frac{p}{q} .$
Month Above/ Below normal (in cm)
May $2.6924$
June $0.6069$
July $- 6.9088$
August $- 8.636$

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Solution

Rainfall in the month of May $= 2.6924 = \frac{26924}{10000} = \frac{26924 \div 4}{10000 \div 4} = \frac{6731}{2500}$
Rainfall in the month of June $= 0.6096 = \frac{6096}{10000} = \frac{6096 \div 16}{10000 \div 16} = \frac{381}{625}$
Rainfall in the month of July $= - 6.9088 = \frac{- 69088}{10000} = - \frac{69088 \div 16}{10000 \div 16} = - \frac{4318}{625}$
Rainfall in the month of August $= - 8.636 = \frac{- 8636}{1000} = - \frac{8636 \div 4}{1000 \div 4} = - \frac{2159}{250}$

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Month	Above/ Below normal (in cm)
May	$2.6924$
June	$0.6069$
July	$- 6.9088$
August	$- 8.636$

Here is a table which gives the information about the total rainfall for several months compared to the average monthly rains of a town. Write each decimal in the form of rational number pq.MonthAbove/ Below normal (in cm)May2.6924June0.6069July−6.9088August−8.636

Here is a table which gives the information about the total rainfall for several months compared to the average monthly rains of a town. Write each decimal in the form of rational number $\frac{p}{q} .$
Month Above/ Below normal (in cm)
May $2.6924$
June $0.6069$
July $- 6.9088$
August $- 8.636$