Question

Heterozygous round and yellow seeded pea plants were selfed and total 800 seeds are collected. What is the total number of seeds with first dominant and second recessive traits?

• A. 950
• B. 300
• C. 200
• D. 150

Answer 1

The correct option is D 150

The F${}_2$ ratio for the dihybrid cross between a heterozygous round and yellow pea plants is 9:3:3:1. The first dominant and second recessive traits will be round and green respectively. It is a recombinant trait. So, as per the ratio, the plants with such a trait will be:

The ratio of recombinant plants

Total Ratio X Total number of plants

$\frac{3}{16}\times 800$ = 150 Plants

Hence, the correct answer is '150'.