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Question

Heterozygous tall and red flowered pea plants are selfed and total 2000 seeds are collected. What is the total number of seeds for both heterozygous traits?

A
250
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B
500
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C
1250
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D
750
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Solution

The correct option is B 500
Gametes TRTr tR tr
TR TTRR- Homozygous Tall and RedTTRr- Homozygous Tall and heterozygous Red TtRR- Heterozygous tall and homozygous Red TtRr-Heterozygous Tall and red
Tr TTRr-Homozygous tall and heterozygous red TTrr-Homozygous Tall and Homozygous white TtRr-Heterozygous Tall and heterozygous Red Ttrr-Heterozygous Tall and homozygous white
tR TtRR-Heterozygous Tall and homozygous Red TtRr-Heterozygous Tall and heterozygous Red
ttRR-Homozygous dwarf and homozygous Red
ttRr-Homozygous dwarf and heterozygous Red
tr TtRr-Heterozygous Tall and heterozygous Red
Ttrr-Heterozygous tall and homozygous red
ttRr- Homozygous dwarf and heterozygous Redttrr-homozygous tall and red
So, the cross is between TtRr x TtRr (where T is dominant on t and gives tallness over dwarfness while the R is dominant over r and gives red colour).
So, on the crossing, we found that out of 16,4 progenies are having both the traits as heterozygous which are highlighted in the cross.
So, out of 2000 progeny seeds formed the number of progenies with heterozygous traits are- 4/16 x 2000
= 500 seeds.
So, the correct answer is '500'.

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