Question

Heterozygous tall and red flowered pea plants are selfed and total 2000 seeds are collected. What is the total number of seeds for both heterozygous traits?

• A. 250
• B. 500
• C. 1250
• D. 750

Answer 1

The correct option is B 500

Gametes	TR	Tr	tR	tr
TR	TTRR- Homozygous Tall and Red	TTRr- Homozygous Tall and heterozygous Red	TtRR- Heterozygous tall and homozygous Red	TtRr-Heterozygous Tall and red
Tr	TTRr-Homozygous tall and heterozygous red	TTrr-Homozygous Tall and Homozygous white	TtRr-Heterozygous Tall and heterozygous Red	Ttrr-Heterozygous Tall and homozygous white
tR	TtRR-Heterozygous Tall and homozygous Red	TtRr-Heterozygous Tall and heterozygous Red	ttRR-Homozygous dwarf and homozygous Red	ttRr-Homozygous dwarf and heterozygous Red
tr	TtRr-Heterozygous Tall and heterozygous Red	Ttrr-Heterozygous tall and homozygous red	ttRr- Homozygous dwarf and heterozygous Red	ttrr-homozygous tall and red

So, the cross is between TtRr x TtRr (where T is dominant on t and gives tallness over dwarfness while the R is dominant over r and gives red colour).

So, on the crossing, we found that out of 16,4 progenies are having both the traits as heterozygous which are highlighted in the cross.

So, out of 2000 progeny seeds formed the number of progenies with heterozygous traits are- 4/16 x 2000

= 500 seeds.

So, the correct answer is '500'.