$H g C l_{2}$ and $I_{2}$ both when dissolved in water containing $I^{-}$ ions, the pair of species formed is:

H g_{2} I_{2}, I^{-}

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H g I_{2}, I_{3}^{-}

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H g I_{2}, I^{-}

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H g I_{4}^{2 -}, I_{3}^{-}

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Solution

The correct option is D $H g I_{4}^{2 -}, I_{3}^{-}$
$H g C l_{2}$ and $I_{2}$ both when dissolved in water containing $I^{-}$ ions the pair of species formed is $H g I_{4}^{2 -}, I_{3}^{-}$ .
$I_{2} + I^{-} \to I_{3}^{-}$
$H g C l_{2} + 4 I^{-} \to H g I_{4}^{2 -} + 2 C l^{-}$ .

Hence, the correct option is $D$ .

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Similar questions

H g C l_{2}

and

I_{2}

both when dissolved in water containing

I^{-}

ions, the pair of species formed is:

H g C l_{2} and I_{2}

both when dissolved in water containing

I^{-}

ions the pair of species formed is :

Q. Assertion: Due to common ion effect, the solubility of

H g I_{2}

is expected to be less in an aqueous solution of KI than in water. But

H g I_{2}

dissolves in an aqueous solution of KI to form a clear solution.
Reason:

I^{⊝}

ion is highly polarisable.

I- ion react with iodine in aqueous solution to form I3- ion .When 1L of solution containing 1mole of KI and 0.25 mol of I2 was reacted with excess of AgNO3 ,0.80 mol of yellow precipitate was formed.The stability constant of. I3- ion is

H g C l_{2} + 4 K I \to K_{2} [H g I_{4}] + 2 K C l

1 mole each of

H g^{2 +}

and

I^{-}

will form how many moles of

H g I_{4}^{2 -}

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HgCl2 and I2 both when dissolved in water containing I− ions, the pair of species formed is:

The correct option is D HgI2−4,I−3HgCl2 and I2 both when dissolved in water containing I−ions the pair of species formed is HgI2−4,I−3.I2+I−→I−3HgCl2+4I−→HgI2−4+2Cl−.Hence, the correct option is D.

$H g C l_{2}$ and $I_{2}$ both when dissolved in water containing $I^{-}$ ions, the pair of species formed is: