Question

Highest oxidation state of manganese in fluoride is $+4\left(Mn{F}_4\right),$ but the highest oxidation state in oxides is $+7\left(M{n}_2{O}_7\right)$ because ____________.

• A. fluorine is more electronegative than oxygen.
• B. In covalent compounds, fluorine can form single bond only while oxygen forms double bond.
• C. fluorine does not possess $d-orbitals.$
• D. fluorine stabilises lower oxidation state.

Answer 1

The correct option is B

In covalent compounds, fluorine can form single bond only while oxygen forms double bond.

• Oxygen has the capability of forming multiple bonds with other elements. Thus, in many manganese-oxygen compounds, oxygen is bonded to Mn through double bonds and oxidises Mn to its highest oxidation state, i.e., $+7.$

• Fluorine can form only single bonds with other elements, i.e., it cannot form double bonds with manganese. So, it oxidises $Mn$ to only $+4$ oxidation state and forms $Mn{F}_4.$


So,option $\left(D\right)$ is the correct Answer.