The correct options are
A Imide
D Amide
Hofmann Bromamide degradation is given by imide and amide.
Acetamide reacts with bromine and aqueous or alcoholic KOH to form methyl amine.
CH3CONH2+Br2+4KOH→CH3NH2+K2CO3+2KBr+2H2O
This is Hoffmann bromamide degradation reaction. The amine formed contains one carbon atom less than amide.