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Question

Homolytic fission of the following alkanes forms free radicals
CH3CH3,CH3CH2CH3,(CH3)2CHCH3,CH3CH2CH(CH3)2.
The increasing order of stability of the radicals is:

A
(CH3)3.C<(CH3)2.CCH2CH3<CH3.CHCH3<CH3.CH2
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B
(CH3)2.CCH2CH3<CH3.CHCH3<CH3.CH2<(CH3)3.C
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C
CH3.CH2<CH3.CHCH3<(CH3)2.CCH2CH3<(CH3)3.C
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D
CH3.CH2<CH3.CHCH3<(CH3)3.C<(CH3)2.CCH2CH3
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