How come $K^{2} + 4 (k + 1)$ is $(k + 2)^{2}$ ?

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Solution

$K^{2} + 4 (K + 1) = K^{2} + 4 K + 4 = K^{2} + 2.2. K + 2^{2} = (K + 2)^{2} [∵ (a + b)^{2} = a^{2} + b^{2} + 2 a b] S o K^{2} + 4 (K + 1) = (K + 2)^{2}$

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