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Byju's Answer
Standard XII
Physics
Position Time Graph
How did we ge...
Question
How did we get the three displacements as 30i^ ;10i^+10√3 j^ ; -45 i^
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Solution
Please provide the sufficien data required to do the problem.
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Similar questions
Q.
If
a
→
=
2
i
^
-
3
j
^
-
k
^
and
b
→
=
i
^
+
4
j
^
-
2
k
^
,
then
a
→
×
b
→
is
(a)
10
i
^
+
2
j
^
+
11
k
^
(b)
10
i
^
+
3
j
^
+
11
k
^
(c)
10
i
^
-
3
j
^
+
11
k
^
(d)
10
i
^
-
2
j
^
-
10
k
^
Q.
How did we get 22/7 as approximate value for pi?
Q.
A force of
(
10
ˆ
i
−
3
ˆ
j
+
6
ˆ
k
)
N
acts on a body of 5 kg and displaces it from
A
(
6
ˆ
i
+
5
ˆ
j
−
3
ˆ
k
)
m
to
B
(
10
ˆ
i
−
2
ˆ
j
+
7
ˆ
k
)
m
. The work done is
Q.
The points with position vectors
10
i
+
3
j
,
12
j
and
a
i
+
11
j
are collinear then a equals.
Q.
The line passing through the points
10
¯
i
+
3
¯
j
,
12
¯
i
+
5
¯
j
also passes through the point
a
¯
i
+
11
¯
j
. Then
a
=
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