Question

How do i calculate$\left(\right)+\left(\right)+\left(\right)=30$ in where i can repeat a number using $1,3,5,7,9,11,13,15$?

Answer 1

Find the required values.

We do not get an outcome of even numbers by adding three odd numbers.

So this sum is only achievable by the factorial approach.

So the answer is

$3!+15+9=30$

Where,

$3!=3✕2✕1$

$3!=6$

So,

$6+15+9=30$

Hence,$(3!)+\left(15\right)+\left(9\right)=30$.