How do I find A- 1 2 -2 -1 3 0 0 -2 1 - - A - -

A=[ 1 amp; 2 amp; 2 1 amp; 3 amp; 0 0 amp; 2 amp; 1 ] #160; #160; ∴| A | #160; =1(3× 1 ( 2× 0) 2( 1 0)+( 2)(2 0) ...

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Standard XII

Mathematics

Equality of Matrices

How do I find...

Question

How do I find
$A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 2 - 1 & 3 & 0 0 & - 2 & 1 \end{matrix} ⎤ ⎥ ⎦ = | A | = ?$

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Solution

$A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 2 - 1 & 3 & 0 0 & - 2 & 1 \end{matrix} ⎤ ⎥ ⎦$
$∴ | A | = 1 (3 \times 1 - (- 2 \times 0) - 2 (- 1 - 0) + (- 2) (2 - 0)$
$= 1 (3) + 2 - 4$
$= 5 - 4$
$= 1$

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⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 2 - 1 & 3 & 0 0 & - 2 & 1 \end{matrix} ⎤ ⎥ ⎦

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Q. Solve the equation

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How do I find A=⎡⎢⎣12−2−1300−21⎤⎥⎦=|A|=?

A=⎡⎢⎣12−2−1300−21⎤⎥⎦∴|A|=1(3×1−(−2×0)−2(−1−0)+(−2)(2−0)=1(3)+2−4=5−4=1

How do I find
$A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 2 - 1 & 3 & 0 0 & - 2 & 1 \end{matrix} ⎤ ⎥ ⎦ = | A | = ?$

$A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 2 - 1 & 3 & 0 0 & - 2 & 1 \end{matrix} ⎤ ⎥ ⎦$
$∴ | A | = 1 (3 \times 1 - (- 2 \times 0) - 2 (- 1 - 0) + (- 2) (2 - 0)$
$= 1 (3) + 2 - 4$
$= 5 - 4$
$= 1$