How does an inductor behave in a d.c circuit ?

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Solution

An Inductor is equivalent to a short circuit to direct current $,$ because once the storage phase has finished $,$ the current $,$ $i L,$ that flows through is stable $, I L = V / R$ no self induced $e . m . f$ is produced and $v L$ is zero $.$ The inductor acts like an oridinary connecting wire $,$ its Resistance is zero $.$

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Obtain the answers (a) to (b) in Exercise 7.13 if the circuit is connected to a high frequency supply (240 V, 10 kHz). Hence, explain the statement that at very high frequency, an inductor in a circuit nearly amounts to an open circuit. How does an inductor behave in a dc circuit after the steady state?

A coil of inductance 0.50 H and resistance

100 Ω

is connected to a 240 V, 50 Hz ac supply.

(a) What is the maximum current in the coil?

(b) What is the time lag between the voltage maximum and the current maximum?

Hence, explain the statement that at very high frequency, an inductor in a circuit nearly amounts to an open circuit. How does an inductor behave in a dc circuit after the steady state?

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Q. Resistors can be used in both AC and DC circuits whereas inductors can only be used in DC circuit.

Q. Prove that an ideal inductor does not dissipate power in an a.c. circuit.

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How does an inductor behave in a d.c circuit ?

An Inductor is equivalent to a short circuit to direct current, because once the storage phase has finished, the current, iL, that flows through is stable,IL=V/R no self induced e.m.f is produced and vL is zero. The inductor acts like an oridinary connecting wire, its Resistance is zero.