How does ozone react with the following :
(i) $P b S$ (ii) $K I$
(iii) $C_{2} H_{4}$ (iv) $N O$

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Solution

Reaction of ozone $(O_{3})$ with:
(i) $P b S$ - Ozone oxidises lead sulphide to lead sulphate. The reaction proceeds at room temperature.
$P b S + 4 O_{3} ⟶ P b S O_{4} Lead sulphate + 4 O_{2}$
(ii) $K I$ - It liberates iodine from a solution of potassium iodide.
$2 K I + O_{3} + H_{2} O ⟶ 2 K O H + O_{2} + I_{2}$
(ii) $C_{2} H_{4}$ - The ozone molecule cleaves the $C = C$ double bond and gives formaldehyde and oxygen gas.
$C_{2} H_{4} + 2 O_{3} ⟶ 2 H C H O Formaldehyde + 2 O_{2}$
(iv) $N O$ - Nitrogen monoxide reacts with ozone to produce nitrogen dioxide and oxygen,
$O_{3} + N O ⟶ N O_{2} + O_{2}$

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How does ozone react with the following :(i) PbS (ii) KI(iii) C2H4 (iv) NO

How does ozone react with the following :
(i) $P b S$ (ii) $K I$
(iii) $C_{2} H_{4}$ (iv) $N O$