Question

How fcc consists of 7/2 atom (i saw in byju solutions)

Answer 1

There are 4 atoms in an fcc unit cell.

1. There are 4 atoms at the corners of the cube which contributes to a single atom. ( 1 ÷8 × 8 corners = 1 atom)
2. There are 6 faces in a cube. An atom contribute 1/2 towards the unit cell. Therefore (1÷ 2 ×6 faces =3 atoms) .

• Therefore from 1 & 2 we get that ,the total no. of atoms in a fcc unit cell is :
• 《1÷8×8=1》+《1÷2×6=3》= 4atoms

the 7/2 in the question is wrong