How is $K M n O_{4}$ is prepared from $M n O_{2}$ ? Write equation.

Open in App

Solution

Pottasium permanganate $({K_{2} M n O}_{4})$ is prepared from pyrdusite ore $({M n O}_{2})$ . The finely powdered pyrolusite ore $({M n O}_{2})$ is fused with an alkali metal hydroxide like $K O H$ in the presence of air an oxidizing agent like ${K N O}_{3}$ to give that dark green pottasium manganate $(K_{2} {M n O}_{4})$ . Pottasium manganate dispropartionate in a neutral / acidic medium to give ${K M n O}_{4}$ .
$2 {H n O}_{2} + 4 K O H + O_{2} ⟶ 2 K_{2} {M n O}_{4} + 2 H_{2} O$
${3 M n O}_{4}^{2 -} + 4 H^{+} \to {2 M n O}_{4}^{-} + {M n O}_{2} + 2 H_{2} O$

Suggest Corrections

Similar questions

K M_{n} O_{4}

M n O_{2}

K M n O_{4}

M n O_{2}

M n O_{2}

K M n O_{4}

M n O_{2} I \to M n O_{4}^{2 -} + M n O_{4}^{-}

K M n O_{4}

K M n O_{4}

M n O_{2}

M n O_{2}

K M n O_{4}

M n O_{2} I \to M n O_{4}^{2 -} I I \to M n O_{4}^{-}

Join BYJU'S Learning Program