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Stoichiometry

How is methyl...

Question

How is methyl cyanide obtained from acetamide?

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Solution

When acetamide is heated with $P_{2} O_{5}$ , a molecule of water is eliminated and methyl cyanide is obtained.
$C H_{3} - C | | O - N H_{2} acetamide P_{2} O_{5} - --- \to - H_{2} O C H_{3} - C \equiv N methyl cyanide$

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Q. Predict the end product in the reaction sequence below :

C_{2} H_{5} N H_{2} H N O_{2} - --- \to (A) P C l_{5} - -- \to (B) N H_{3} - -- \to (C)

Q. Which of the following is obtained by reducing methyl cyanide with

N a + C_{2} H_{5} O H

?

Q. Methyl cyanide on reaction with sodium and

C_{2} H_{5} O H

Q. Assertion :Methyl cyanide has higher boiling point than methyl isocyanide. Reason: Dipole moment of methyl cyanide is higher than that of methyl isocyanide.

Q. I.U.P.A.C name of methyl cyanide is:

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