Question

How it became 88=2x2x2x11=2(3)x11(1)(3+1)(1+1)=4x2=8

Answer 1

This is the method to find no.of factors for a given no.

Here No.=88

Steps include

1. The prime factorization: 88 = (2^3)(11^1)
2. The powers: 3 and 1
3. Add one to the powers: 4 and 2
4. Multiply the results: (4)(2) = 8

That 's how to find no.of factors for a given no.

So here no.of factors for 88 =8