Question

How long will a current of 1 ampere take for complete deposition of copper from 1 litre of

1N CuSO${}_4$. 5H${}_2$O solution?

• A. $96500sec$
• B. $2\times 96500sec$
• C. $\left[\frac{96500}{2}\right]sec$
• D. $\left[\frac{96500}{4}\right]sec$

Answer 1

The correct option is A $96500sec$

1 litre of 1 normality solution.

$\therefore$ 1 equivalent of the CuSO${}_4$.$5H_{2}O$ is present

$\therefore \text{charge present}=1Faraday$

$Q=I\times t$

$\therefore t=\frac{Q}{I}=\frac{96500}{1}sec$

$t=96500sec$

Option A is correct.