How long will it take to stop a car travelling at a speed of 30 m/s, if the uniform acceleration during braking is $- 6 m / s^{2}$ .

\frac{1}{5} s

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\frac{1}{10} s

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10 s

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5 s

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Solution

The correct option is D 5 s
Initial velocity, u = 30 m/s
Acceleration, $a = - 6 m / s^{2}$
Final velocity, v = 0
Using first equation of motion, v = u + at
Time, $t = \frac{v - u}{a}$
$\Rightarrow t = \frac{0 - 30}{- 6} = 5 s$
Hence, the correct answer is option (d).

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Similar questions

The brakes applied to a car produce a negative acceleration of $a = 6 m s^{- 2}$ . If the car takes 2 seconds to stop after applying the brakes, calculate the distance it travels during this time. (Give your answer in m).

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The brakes applied by a car produces an acceleration of $6 m / s^{2}$ in opposite direction of motion. If the car takes 2 sec to stop after the application of brakes. Calculate distance during this time.

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How long will it take to stop a car travelling at a speed of 30 m/s, if the uniform acceleration during braking is –6m/s2.

The correct option is D 5 sInitial velocity, u = 30 m/s Acceleration, a=–6m/s2 Final velocity, v = 0 Using first equation of motion, v = u + at Time, t=v−ua ⇒t=0−30−6=5s Hence, the correct answer is option (d).

How long will it take to stop a car travelling at a speed of 30 m/s, if the uniform acceleration during braking is $- 6 m / s^{2}$ .

The correct option is D 5 s
Initial velocity, u = 30 m/s
Acceleration, $a = - 6 m / s^{2}$
Final velocity, v = 0
Using first equation of motion, v = u + at
Time, $t = \frac{v - u}{a}$
$\Rightarrow t = \frac{0 - 30}{- 6} = 5 s$
Hence, the correct answer is option (d).