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Question

How many 3 -digit even numbers can be formed from the digit 1,2,3,4,5,6 if digits can be repeated ?

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Solution

To be a even number the number should end with either 2,4 or 6.
Possibilities at unit’s place =3
So, ten’s place can have 6 numbers.
Possibilities at ten’s place =6
Therefore, at the hundred’s place there can be 6 of the 6 numbers.
Possibilities at hundred’s place =6.
Total number of possibilities=3×6×6=108 ways


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