CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How many 3-digit numbers can be formed by the digits 5, 2, and 8 without repeating any digit in the number?

A
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 6
Number 1 = 528
Number 2 = 582
Number 3 = 852
Number 4 = 825
Number 5 = 258
Number 6 = 285
Hence, 6 numbers can be formed by arranging the digits 5, 2, and 8 without repeating any number.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Graphical Representation of Data
Watch in App
Join BYJU'S Learning Program
CrossIcon