Question

How many $6$-digit numbers can be formed from the digits $0,1,3,5,7$ and $9$ which are divisible by 10 and no digit is repeated ?

Answer 1

A number divisble by 10 will have last digit as $0$

So, now excluding the last digit

we can arrange remaining digits to make different numbers in

$5!$ ways

Hence, Answer is $5!=120$