Question

How many six digit numbers can be formed from the digits $1,2,3,4,5,6$ which are divisible by$4$ and digits are not repeated?

• A. $122$
• B. $192$
• C. $164$
• D. $155$

Answer 1

Answer: (B)

$192$

Since the number should be divisible by $4$ the last $2$ digit must be one of the following $:12,16,24,32,36,52,56,64=8$ Possibilities.

The first $4$ digits can be filled by the remaining $4$ numbers in each case.

$\Rightarrow$ Permutations $=8\times {}^4{P}_4=8\times 4!=192.$

Hence, the answer is $192.$