How many acyclic structural isomers of C4H7Cl is possible?
A
10
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B
5
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C
6
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D
8
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Solution
The correct option is D 8 For a compound with molecular formula CcHhXxNnOo Degree of unsaturation=(c+1)−h2−x2+n2
Where, X = Halogen
c=number of carbon atom
h=number of hydrogen atom
n=number of nitrogen atom
o=number of oxygen atom
In C4H7Cl Degree of unsaturation=(4+1)−72−12=1
There are 6 possible acyclic structural isomer of C4H7Cl