How many Ag atoms are there in 0.0001 gms of Ag atoms(Molar mass of Ag is 108 gram per molecule)?

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Solution

Molar mass of Ag = 108 g mol^-1
$108 g o f A g c o n t a i n s = 6.022 \times 10^{23} a t o m s o f A g 0.0001 g o f A g = \frac{6.022 \times 10^{23}}{0.0001} = 5.57 \times 10^{17} a t o m s$

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