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Question

How many amide isomers are possible for C4H9ON ?

A
8
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B
6
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C
5
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D
4
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Solution

The correct option is A 8
For a compound with molecular formula CcHhXxNnOo
Degree of unsaturation=(c+1)h2x2+n2
Where, X = Halogen
c=number of carbon atom
h=number of hydrogen atom
n=number of nitrogen atom
o=number of oxygen atom
In C4H9ON?
Degree of unsaturation=(4+1)92+12=1
Compound has one degree of unsaturation, it can be an amide as it contains one nitrogen and one oxygen atoms.
Hence, a total of 8 isomers are possible.

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