How many atomic orbitals are involved in hybridization of [Co(NH $_{3}$ ) $_{6}$ ] $^{2 +}$ ?

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Solution

Six atomic orbitals are involved in hybridization of [Co(NH $_{3}$ ) $_{6}$ ] $^{2 +}$ . In this complex, the central Co atom undergoes $d^{2} s p^{3}$ hybridization. Thus total number of atomic orbitals involved is $2 + 1 + 3 = 6$ .
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