Atomic orbitals involved in hybridization of $S F_{6}$ molecule:

3 s, 3 p_{x}, 3 p_{y}, 3 p_{z}, 3 d_{z^{2}}, 3 d_{x^{2} - y^{2}}

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3 s, 3 p_{x}, 3 p_{y}, 3 p_{z}, 3 d_{z^{2}}

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4 s, 4 p_{x}, 4 p_{y}, 4 p_{z}, 3 d_{x^{2} - y^{2}}, d_{x y}

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3 s, 3 p_{x}, 3 p_{y}, 3 d_{x y}, 3 d_{y z}, 3 d_{x z}

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Solution

The correct option is A $3 s, 3 p_{x}, 3 p_{y}, 3 p_{z}, 3 d_{z^{2}}, 3 d_{x^{2} - y^{2}}$
The $S F_{6}$ molecule involves ${s p}^{3} d^{2}$ hybridisation and the geometry of molecule is octahedral and atomic orbitals which are involved in the hybridisation is: $3 s, 3 p_{x}, {3 p}_{y}, {3 p}_{z}, {3 d}_{x^{2} - y^{2}}, {3 d}_{Z^{2}}$

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H -

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