Question

How many atoms are present in each element of CaCO3 which is in 50g

Answer 1

$$\begin{gathered} \text{Dear student,} \\ 100\mathrm{g}\mathrm{of}{\mathrm{CaCO}}_3\mathrm{contain}=6.022\times {10}^{23}\mathrm{molecules} \\ 50\mathrm{g}\mathrm{of}{\mathrm{CaCO}}_3\mathrm{contain}=\frac{6.022\times {10}^{23}}{100}\times 50\mathrm{molecules}=3.011\times {10}^{23}\mathrm{molecules} \\ 1\mathrm{molecule}\mathrm{of}{\mathrm{CaCO}}_3\mathrm{contain}=5\mathrm{atoms} \\ 3.011\times {10}^{23}\mathrm{molecules}\mathrm{of}{\mathrm{CaCO}}_3\mathrm{contain}=5\times 3.011\times {10}^{23}\mathrm{atoms}=1.5055\times {10}^{24}\mathrm{atoms} \\ \mathrm{Regards} \end{gathered}$$