How many base pairs in the gene are needed to code for the enzyme lysozyme, containing $129$ amino acids, found in egg white?

3 \times 129

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(3 \times 129) + (3 \times 2) = 393

base pairs

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(3 \times 129) + (3 \times 3) = 396

base pairs

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4 \times 129

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Solution

The correct option is C $(3 \times 129) + (3 \times 2) = 393$ base pairs
Three base pairs code for one amino acid and two more triplets are required for 'start' and 'stop' signals, or $(3 \times 129) + (3 \times 2) = 393$ base pairs in the gene are needed to code for the enzyme lysozyme, containing $129$ amino acids, found in egg white.

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How many base pairs in the gene are needed to code for the enzyme lysozyme, containing 129 amino acids, found in egg white?

The correct option is C (3×129)+(3×2)=393 base pairsThree base pairs code for one amino acid and two more triplets are required for 'start' and 'stop' signals, or (3×129)+(3×2)=393 base pairs in the gene are needed to code for the enzyme lysozyme, containing 129 amino acids, found in egg white.

How many base pairs in the gene are needed to code for the enzyme lysozyme, containing $129$ amino acids, found in egg white?