Question

How many carbon atoms are present in 0.35 mol of $C_6{H}_{12}{O}_6$:

• A. $6.023\times {10}^{23}$ carbon atoms
• B. $1.26\times {10}^{23}$ carbon atoms
  
• C. $1.26\times {10}^{24}$ carbon atoms
  
• D. $6.023\times {10}^{24}$ carbon atoms

Answer 1

The correct option is B $1.26\times {10}^{23}$ carbon atoms


$\therefore$ 1 mol of $C_6{H}_{12}{O}_6$ has = 6 $N_A$ atoms of C $\therefore$ 0.35 mol of $C_6{H}_{12}{O}_6$ = $6\times 0.35$ $N_A$ atoms of C = 2.1 $N_A$ atoms
= $2.1\times 6.022\times {10}^{23}=1.26\times {10}^{24}$ carbon atoms