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Question

# How many chlorine atoms can you ionize in the process Cl+e−→Cl++e−, by the energy liberated from the following process: Cl+e−→Cl−for 6×1023 atoms given electron affinity of chlorine is 3.61 eV and ionization energy of chlorine is 17.422 eV

A
1.243×1022 atoms
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B
1.243×1023 atoms
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C
2.243×1022 atoms
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D
2.243×1023 atoms
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Solution

## The correct option is B 1.243×1023 atoms Energy released in conversion of =6×1023 atoms to Cl− ions. =6×1023×electron affinity=6×1023×3.61=2.166×1024 eV Let x, chlorine atoms are conversed to Cl+ ion. Energy absorbed =N×ionization energy=N×17.422 eV ∴N×17.422 eV=2.166×1024 N=1.243×1023 atoms hence, number of chlorine atom = 1.243×1023 atoms

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