How many different numbers of 6 digits can be formed with the numbers 3, 1, 7, 0, 9, 5?

500

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400

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300

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600

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None of these

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Solution

The correct option is D 600
The numbers that can be formed, by taking all 6 digits together
$=^{6} P_{6} = 6!$
But we have to neglect the numbers which begin with zero. Now, the numbers in which zero comes in the 1st place = 5!
Hence, the required number = 6! - 5!
= 720 - 120 = 600.

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