CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

How many different three digit numbers can be formed with the digits 1, 2, 3, 4, 5 and 6 so that none of the digits are repeated?
  1. 120  
  2. 80  
  3. 130  
  4. 150  
  5. 100  


Solution

The correct option is A 120  

Suppose we start with the unit’s place. Unit place can be filled by any of the 6 digits given, so it can be filled in 6 ways. Now coming the tens place, it can be filled by any of the six digits except the one which has been used at unit’s place. So, it can be filled in 5 ways. Similarly the hundred’s place can be filled by any of the six digits except those two which have been used at unit’s and tens’ place. So, it can be filled in 4 ways.

4 ways   5 ways   6 ways

 So, total numbers of numbers possible = 6×5×4=120. Hence option (a)

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image