How many different numbers of six digits can be formed from the digits 3,1,7,0,9,5 when repetition of digits is not allowed ?
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Solution
We cannot have 0 at the first digit of six-digit numbers. Now, 5 digits are left including 0. So, second digit of six-digit numbers can be selected in 5 ways. Third digit of six-digit numbers can be selected in 4 ways. Fourth digit of six-digit numbers can be selected in 3 ways. Fifth digit of six-digit numbers can be selected n 2 ways. Last digit of six-digit numbers can be selected in 1 ways. Hence, total number of numbers = 5×5×4×3×2×1=600